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BCH + BAG = 120°

X = 3, Y = 6

Angle aPB = 108

Orange Area = 47.1238898038

BE = X = 1.59807621135

White Area = 257.879248594

White Area = 575

3-4-5-Triangle with Incircle

If AC = 8 ...

Shaded Fraction = 1 / 2

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Red / Orange = 1 / 3 ⇒ Blue / Green = 1

DF = sqrt 2 = 1.41421356237

Line Segment DE = 6.78822509939

Angle CBE = 40°

X / Y = 1.48445439794

Ratio b / a = 17.94427191

Ratio a / b = 2

Angle KTP = 135°

Angle AOP = α = 15°

Angle GAP = 24

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Area of Orange Triangle = 12

Orange Area = 100

tan CPT has Many Solutions

Orange = 20 ⇒ Blue = 15

Blue Area = 27.0783760577

r = 3, R = 25

Radius = 1.835856849095

Radius = ? ( Formula )

r = 1, R = 4.03112887415

Angle BHJ = 150°

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X / Y = ϕ = 1.61803398875

Growing Circle, Semicircle 3

Mauve Area = 12.5663706144

Fraction = 0.214737233855

Green Area / Red Area = 4

Red Area / Blue Area = 1

Fraction = 5.82842712475

CAD = X = 25.7142857143

Area of Triangle = 22

Radius = 1.6049935249414

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Orange Area = 49 / 2

Orange Area = 6

Shaded Fraction = 0.41452991453

Time = 3

Base KN = 3.46410161514

DE = X = 7

Red Area = 13

Mauve Area = 108

EG = X = 2.05314157066

DE = K = 4