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Total Area = 9.472135955

 

Shaded = 100.530964915

Angle AED = X = 30°

| AD | + | AE | = 29

Angle ADE = X = 28°

Line Segment EG = 119

Line Segment AC = X = 11

Ratio of Yellow / Blue = 2 / 1

Blue = hw = 8 Square Units

X = Radius = 24

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Shaded Fraction = 1 / 13

Area of Square = 6 Sq. Units

Shaded Area = 117 Sq. Units

Pink Area = 90 Square Units

Ratio of A : B : C = 9 : 4 : 3

Rectangle = 30 Square Units

Improved: X = 1.76640701183

Animated: X = 1.76640701183

Improved: Blue / Total = 2 / 9

Blue / Total = 2 / 9

Line Segment BC = X = 8

α = ∠ HAI = 18°

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Isosceles Triangle

Diameter AB = 2R = 9

Shaded Fraction = 1 / 4

R = 5 ⇒ Shaded Area = 16

EF = 12 ⇒ CF = X = 8

Ratio = ϕ = 1.61803398875

Ratio of AB / BC = 4 / 1

Shaded Fraction = 1 / 2 = 0.5

Radius R = 2.25

There are Many Solutions

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Traditional Approach

Radius R₂ = 2.44897959184

Ratio = 0.555441681549

Ratio = 0.0481125224325

Green / Orange = 0.25 = 1 / 4

Side s of Square ABCD = 12

Ratio of Red : Blue = 25 : 1

Proof regarding Bisector t

Angle DLN = X = 45°

Four Circles

Blue Area = 6.63225115758

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Fraction = 0.48 = 12 / 25

Radius R = 4.82842712475

0.444444444444 = 4 / 9

Pink Area = Blue Area

B, E and F are Colinear

X = −2.17867781294

Major Circle = 4 Square Units

Improved

Radius R = 4.82842712475

Improved

Circle Area = 14.5103949139

Improved

Line Segment DE = 6.5